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NEW QUESTION 47
Which of the following code blocks creates a new DataFrame with two columns season and wind_speed_ms where column season is of data type string and column wind_speed_ms is of data type double?

  • A. CharType()), T.StructField("season", T.DoubleType())]))
  • B. spark.createDataFrame({"season": ["winter","summer"], "wind_speed_ms": [4.5, 7.5]})
  • C. spark.createDataFrame([("summer", 4.5), ("winter", 7.5)], ["season", "wind_speed_ms"])
  • D. 1. from pyspark.sql import types as T
    2. spark.createDataFrame((("summer", 4.5), ("winter", 7.5)), T.StructType([T.StructField("season",
  • E. spark.DataFrame({"season": ["winter","summer"], "wind_speed_ms": [4.5, 7.5]})
  • F. spark.newDataFrame([("summer", 4.5), ("winter", 7.5)], ["season", "wind_speed_ms"])

Answer: C

Explanation:
Explanation
spark.createDataFrame([("summer", 4.5), ("winter", 7.5)], ["season", "wind_speed_ms"]) Correct. This command uses the Spark Session's createDataFrame method to create a new DataFrame. Notice how rows, columns, and column names are passed in here: The rows are specified as a Python list. Every entry in the list is a new row. Columns are specified as Python tuples (for example ("summer", 4.5)). Every column is one entry in the tuple.
The column names are specified as the second argument to createDataFrame(). The documentation (link below) shows that "when schema is a list of column names, the type of each column will be inferred from data" (the first argument). Since values 4.5 and 7.5 are both float variables, Spark will correctly infer the double type for column wind_speed_ms. Given that all values in column
"season" contain only strings, Spark will cast the column appropriately as string.
Find out more about SparkSession.createDataFrame() via the link below.
spark.newDataFrame([("summer", 4.5), ("winter", 7.5)], ["season", "wind_speed_ms"]) No, the SparkSession does not have a newDataFrame method.
from pyspark.sql import types as T
spark.createDataFrame((("summer", 4.5), ("winter", 7.5)), T.StructType([T.StructField("season",
T.CharType()), T.StructField("season", T.DoubleType())]))
No. pyspark.sql.types does not have a CharType type. See link below for available data types in Spark.
spark.createDataFrame({"season": ["winter","summer"], "wind_speed_ms": [4.5, 7.5]}) No, this is not correct Spark syntax. If you have considered this option to be correct, you may have some experience with Python's pandas package, in which this would be correct syntax. To create a Spark DataFrame from a Pandas DataFrame, you can simply use spark.createDataFrame(pandasDf) where pandasDf is the Pandas DataFrame.
Find out more about Spark syntax options using the examples in the documentation for SparkSession.createDataFrame linked below.
spark.DataFrame({"season": ["winter","summer"], "wind_speed_ms": [4.5, 7.5]}) No, the Spark Session (indicated by spark in the code above) does not have a DataFrame method.
More info: pyspark.sql.SparkSession.createDataFrame - PySpark 3.1.1 documentation and Data Types - Spark 3.1.2 Documentation Static notebook | Dynamic notebook: See test 1

 

NEW QUESTION 48
The code block displayed below contains an error. When the code block below has executed, it should have divided DataFrame transactionsDf into 14 parts, based on columns storeId and transactionDate (in this order). Find the error.
Code block:
transactionsDf.coalesce(14, ("storeId", "transactionDate"))

  • A. The parentheses around the column names need to be removed and .select() needs to be appended to the code block.
  • B. Operator coalesce needs to be replaced by repartition, the parentheses around the column names need to be removed, and .count() needs to be appended to the code block.
    (Correct)
  • C. Operator coalesce needs to be replaced by repartition.
  • D. Operator coalesce needs to be replaced by repartition, the parentheses around the column names need to be removed, and .select() needs to be appended to the code block.
  • E. Operator coalesce needs to be replaced by repartition and the parentheses around the column names need to be replaced by square brackets.

Answer: B

Explanation:
Explanation
Correct code block:
transactionsDf.repartition(14, "storeId", "transactionDate").count()
Since we do not know how many partitions DataFrame transactionsDf has, we cannot safely use coalesce, since it would not make any change if the current number of partitions is smaller than 14.
So, we need to use repartition.
In the Spark documentation, the call structure for repartition is shown like this:
DataFrame.repartition(numPartitions, *cols). The * operator means that any argument after numPartitions will be interpreted as column. Therefore, the brackets need to be removed.
Finally, the question specifies that after the execution the DataFrame should be divided. So, indirectly this question is asking us to append an action to the code block. Since .select() is a transformation. the only possible choice here is .count().
More info: pyspark.sql.DataFrame.repartition - PySpark 3.1.1 documentation Static notebook | Dynamic notebook: See test 1

 

NEW QUESTION 49
Which of the following describes the difference between client and cluster execution modes?

  • A. In cluster mode, the driver runs on the master node, while in client mode, the driver runs on a virtual machine in the cloud.
  • B. In cluster mode, each node will launch its own executor, while in client mode, executors will exclusively run on the client machine.
  • C. In cluster mode, the driver runs on the edge node, while the client mode runs the driver in a worker node.
  • D. In cluster mode, the driver runs on the worker nodes, while the client mode runs the driver on the client machine.
  • E. In client mode, the cluster manager runs on the same host as the driver, while in cluster mode, the cluster manager runs on a separate node.

Answer: D

Explanation:
Explanation
In cluster mode, the driver runs on the master node, while in client mode, the driver runs on a virtual machine in the cloud.
This is wrong, since execution modes do not specify whether workloads are run in the cloud or on-premise.
In cluster mode, each node will launch its own executor, while in client mode, executors will exclusively run on the client machine.
Wrong, since in both cases executors run on worker nodes.
In cluster mode, the driver runs on the edge node, while the client mode runs the driver in a worker node.
Wrong - in cluster mode, the driver runs on a worker node. In client mode, the driver runs on the client machine.
In client mode, the cluster manager runs on the same host as the driver, while in cluster mode, the cluster manager runs on a separate node.
No. In both modes, the cluster manager is typically on a separate node - not on the same host as the driver. It only runs on the same host as the driver in local execution mode.
More info: Learning Spark, 2nd Edition, Chapter 1, and Spark: The Definitive Guide, Chapter 15. ()

 

NEW QUESTION 50
The code block shown below should return a copy of DataFrame transactionsDf with an added column cos.
This column should have the values in column value converted to degrees and having the cosine of those converted values taken, rounded to two decimals. Choose the answer that correctly fills the blanks in the code block to accomplish this.
Code block:
transactionsDf.__1__(__2__, round(__3__(__4__(__5__)),2))

  • A. 1. withColumn
    2. col("cos")
    3. cos
    4. degrees
    5. transactionsDf.value
  • B. 1. withColumn
    2. "cos"
    3. cos
    4. degrees
    5. transactionsDf.value
  • C. 1. withColumn
    2. col("cos")
    3. cos
    4. degrees
    5. col("value")
    E
    . 1. withColumn
    2. "cos"
    3. degrees
    4. cos
    5. col("value")
  • D. 1. withColumnRenamed
    2. "cos"
    3. cos
    4. degrees
    5. "transactionsDf.value"

Answer: B

Explanation:
Explanation
Correct code block:
transactionsDf.withColumn("cos", round(cos(degrees(transactionsDf.value)),2)) This question is especially confusing because col, "cos" are so similar. Similar-looking answer options can also appear in the exam and, just like in this question, you need to pay attention to the details to identify what the correct answer option is.
The first answer option to throw out is the one that starts with withColumnRenamed: The question NO:
speaks specifically of adding a column. The withColumnRenamed operator only renames an existing column, however, so you cannot use it here.
Next, you will have to decide what should be in gap 2, the first argument of transactionsDf.withColumn().
Looking at the documentation (linked below), you can find out that the first argument of withColumn actually needs to be a string with the name of the column to be added. So, any answer that includes col("cos") as the option for gap 2 can be disregarded.
This leaves you with two possible answers. The real difference between these two answers is where the cos and degree methods are, either in gaps 3 and 4, or vice-versa. From the question you can find out that the new column should have "the values in column value converted to degrees and having the cosine of those converted values taken". This prescribes you a clear order of operations: First, you convert values from column value to degrees and then you take the cosine of those values. So, the inner parenthesis (gap 4) should contain the degree method and then, logically, gap 3 holds the cos method. This leaves you with just one possible correct answer.
More info: pyspark.sql.DataFrame.withColumn - PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 3

 

NEW QUESTION 51
Which of the following statements about lazy evaluation is incorrect?

  • A. Execution is triggered by transformations.
  • B. Lineages allow Spark to coalesce transformations into stages
  • C. Spark will fail a job only during execution, but not during definition.
  • D. Accumulators do not change the lazy evaluation model of Spark.
  • E. Predicate pushdown is a feature resulting from lazy evaluation.

Answer: A

Explanation:
Explanation
Execution is triggered by transformations.
Correct. Execution is triggered by actions only, not by transformations.
Lineages allow Spark to coalesce transformations into stages.
Incorrect. In Spark, lineage means a recording of transformations. This lineage enables lazy evaluation in Spark.
Predicate pushdown is a feature resulting from lazy evaluation.
Wrong. Predicate pushdown means that, for example, Spark will execute filters as early in the process as possible so that it deals with the least possible amount of data in subsequent transformations, resulting in a performance improvements.
Accumulators do not change the lazy evaluation model of Spark.
Incorrect. In Spark, accumulators are only updated when the query that refers to the is actually executed. In other words, they are not updated if the query is not (yet) executed due to lazy evaluation.
Spark will fail a job only during execution, but not during definition.
Wrong. During definition, due to lazy evaluation, the job is not executed and thus certain errors, for example reading from a non-existing file, cannot be caught. To be caught, the job needs to be executed, for example through an action.

 

NEW QUESTION 52
......

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