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NEW QUESTION 32
You are working on a functional bug in a tool used by your development organization. In your investigation, you find that the tool is executed with a security policy file containing this grant.

What action should you take?

• A. Nothing, because listing just the required permissions would be an ongoing maintenance challenge.
• B. File a security bug against the tool referencing the excessive permission granted.
• C. Nothing, because it is not related to the bug you are investigating.
• D. Remove the grant because it is excessive.
• E. Nothing, because it is an internal tool and not exposed to the public.

Answer: B

NEW QUESTION 33
Given:

You want to examine the items list it contains an item for which the variable count is below zero.
Which code fragment at line 1 accomplish this?

• A. If (items.stream () .filter (i -> count < 0) . findAny () ) {
• B. If (items.stream () .allmatch (i -> count < 0) < 0) ) {
• C. If (items.stream () .anymatch (i -> count < 0) < 0) ) {
• D. If (items.stream () .filter (i -> count < 0) . findFirst () ) {

Answer: D

NEW QUESTION 34
Which declaration of an annotation type is legal?
@interface Author {

• A. String name() default null;
  String date();
  }
  @interface Author {
• B. String name() default "";
  String date();
  }
  @interface Author {
• C. String name() default "";
  String date();
  }
  @interface Author extends Serializable {
• D. String name();
  String date;
  }
  @interface Author {
• E. String name();
  String date default "";
  }

Answer: C

NEW QUESTION 35
Given:

Which two are correct? (Choose two.)

• A. Option D
• B. Option A
• C. Option C
• D. Option B

Answer: A,C

NEW QUESTION 36
Given:
var fruits = List.of("apple", "orange", "banana", "lemon");
You want to examine the first element that contains the character n. Which statement will accomplish this?

• A. Optional<String> result = fruits.stream().filter(f > f.contains ("n")).findFirst ();
• B. fruits.stream().filter(f > f.contains("n")).forEachOrdered(System.out::print);
• C. Optional<String> result = fruits.stream().anyMatch(f > f.contains("n"));
• D. String result = fruits.stream().filter(f > f.contains("n")).findAny();

Answer: B

Explanation:

NEW QUESTION 37
......